Base | Representation |
---|---|
bin | 110001011000011100… |
… | …010111110010101010 |
3 | 12001212021221211122200 |
4 | 301120130113302222 |
5 | 1332043000040132 |
6 | 40205244201030 |
7 | 3554653542516 |
oct | 613034276252 |
9 | 161767854580 |
10 | 53023440042 |
11 | 2053a393331 |
12 | a339539176 |
13 | 50002703c1 |
14 | 27d00b9146 |
15 | 15a5018d7c |
hex | c58717caa |
53023440042 has 48 divisors (see below), whose sum is σ = 116849791968. Its totient is φ = 17372478240.
The previous prime is 53023440017. The next prime is 53023440059. The reversal of 53023440042 is 24004432035.
53023440042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×530234400422 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53023439988 and 53023440015.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1612053 + ... + 1644615.
It is an arithmetic number, because the mean of its divisors is an integer number (2434370666).
Almost surely, 253023440042 is an apocalyptic number.
53023440042 is an abundant number, since it is smaller than the sum of its proper divisors (63826351926).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53023440042 is a wasteful number, since it uses less digits than its factorization.
53023440042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34115 (or 34112 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 27.
Adding to 53023440042 its reverse (24004432035), we get a palindrome (77027872077).
The spelling of 53023440042 in words is "fifty-three billion, twenty-three million, four hundred forty thousand, forty-two".
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