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5302432255433 is a prime number
BaseRepresentation
bin100110100101001000110…
…0101110100110111001001
3200202220111121202112100212
41031022101211310313021
51143333340124133213
615135523113210505
71055042133342305
oct115122145646711
920686447675325
105302432255433
111764826857315
12717791a00a35
132c602ba93271
141448d3942d05
1592ddd6c89a8
hex4d291974dc9

5302432255433 has 2 divisors, whose sum is σ = 5302432255434. Its totient is φ = 5302432255432.

The previous prime is 5302432255399. The next prime is 5302432255441. The reversal of 5302432255433 is 3345522342035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4048755671104 + 1253676584329 = 2012152^2 + 1119677^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5302432255433 is a prime.

It is not a weakly prime, because it can be changed into another prime (5302432255633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651216127716 + 2651216127717.

It is an arithmetic number, because the mean of its divisors is an integer number (2651216127717).

Almost surely, 25302432255433 is an apocalyptic number.

It is an amenable number.

5302432255433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5302432255433 is an equidigital number, since it uses as much as digits as its factorization.

5302432255433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296000, while the sum is 41.

Adding to 5302432255433 its reverse (3345522342035), we get a palindrome (8647954597468).

The spelling of 5302432255433 in words is "five trillion, three hundred two billion, four hundred thirty-two million, two hundred fifty-five thousand, four hundred thirty-three".