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530245312521 = 3176748437507
BaseRepresentation
bin1111011011101010001…
…01010110000000001001
31212200122201002210010120
413231311011112000021
532141420300000041
61043331421133453
753210654535141
oct7556505260011
91780581083116
10530245312521
1119496a723451
12869220ba289
133b0042a3ac2
141b942087921
15dbd6067366
hex7b75156009

530245312521 has 4 divisors (see below), whose sum is σ = 706993750032. Its totient is φ = 353496875012.

The previous prime is 530245312477. The next prime is 530245312523. The reversal of 530245312521 is 125213542035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 530245312521 - 211 = 530245310473 is a prime.

It is not an unprimeable number, because it can be changed into a prime (530245312523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88374218751 + ... + 88374218756.

It is an arithmetic number, because the mean of its divisors is an integer number (176748437508).

Almost surely, 2530245312521 is an apocalyptic number.

It is an amenable number.

530245312521 is a deficient number, since it is larger than the sum of its proper divisors (176748437511).

530245312521 is a wasteful number, since it uses less digits than its factorization.

530245312521 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176748437510.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 530245312521 its reverse (125213542035), we get a palindrome (655458854556).

The spelling of 530245312521 in words is "five hundred thirty billion, two hundred forty-five million, three hundred twelve thousand, five hundred twenty-one".

Divisors: 1 3 176748437507 530245312521