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5302511220433 = 72841532665823
BaseRepresentation
bin100110100101001011001…
…0011000011011011010001
3200202220201010100100222111
41031022112103003123101
51143334020333023213
615135535013505321
71055044112465050
oct115122623033321
920686633310874
105302511220433
111764867390949
127177b4342241
132c604225050b
1414490021a397
1592de55c5a3d
hex4d2964c36d1

5302511220433 has 8 divisors (see below), whose sum is σ = 6060036423168. Its totient is φ = 4544991917664.

The previous prime is 5302511220379. The next prime is 5302511220437. The reversal of 5302511220433 is 3340221152035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5302511220433 - 221 = 5302509123281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5302511220395 and 5302511220404.

It is not an unprimeable number, because it can be changed into a prime (5302511220437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 656160 + ... + 3321982.

It is an arithmetic number, because the mean of its divisors is an integer number (757504552896).

Almost surely, 25302511220433 is an apocalyptic number.

It is an amenable number.

5302511220433 is a deficient number, since it is larger than the sum of its proper divisors (757525202735).

5302511220433 is a wasteful number, since it uses less digits than its factorization.

5302511220433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2949983.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 5302511220433 its reverse (3340221152035), we get a palindrome (8642732372468).

The spelling of 5302511220433 in words is "five trillion, three hundred two billion, five hundred eleven million, two hundred twenty thousand, four hundred thirty-three".

Divisors: 1 7 284153 1989071 2665823 18660761 757501602919 5302511220433