Base | Representation |
---|---|
bin | 100110100101001011001… |
… | …1110000101000010001001 |
3 | 200202220201022210012112202 |
4 | 1031022112132011002021 |
5 | 1143334022103014401 |
6 | 15135535155445545 |
7 | 1055044146163151 |
oct | 115122636050211 |
9 | 20686638705482 |
10 | 5302514110601 |
11 | 1764868a85314 |
12 | 7177b52b68b5 |
13 | 2c6042a22b86 |
14 | 14490076d761 |
15 | 92de599706b |
hex | 4d296785089 |
5302514110601 has 2 divisors, whose sum is σ = 5302514110602. Its totient is φ = 5302514110600.
The previous prime is 5302514110591. The next prime is 5302514110613. The reversal of 5302514110601 is 1060114152035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4408420941376 + 894093169225 = 2099624^2 + 945565^2 .
It is a cyclic number.
It is not a de Polignac number, because 5302514110601 - 238 = 5027636203657 is a prime.
It is not a weakly prime, because it can be changed into another prime (5302514110001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651257055300 + 2651257055301.
It is an arithmetic number, because the mean of its divisors is an integer number (2651257055301).
Almost surely, 25302514110601 is an apocalyptic number.
It is an amenable number.
5302514110601 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302514110601 is an equidigital number, since it uses as much as digits as its factorization.
5302514110601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 5302514110601 its reverse (1060114152035), we get a palindrome (6362628262636).
The spelling of 5302514110601 in words is "five trillion, three hundred two billion, five hundred fourteen million, one hundred ten thousand, six hundred one".
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