Base | Representation |
---|---|
bin | 110001011000100011… |
… | …010001110111000001 |
3 | 12001212102100211111001 |
4 | 301120203101313001 |
5 | 1332043431011003 |
6 | 40205351052001 |
7 | 3555005123536 |
oct | 613043216701 |
9 | 161772324431 |
10 | 53025250753 |
11 | 2054040a792 |
12 | a33a071001 |
13 | 5000755627 |
14 | 27d042ad8d |
15 | 15a527561d |
hex | c588d1dc1 |
53025250753 has 2 divisors, whose sum is σ = 53025250754. Its totient is φ = 53025250752.
The previous prime is 53025250739. The next prime is 53025250757. The reversal of 53025250753 is 35705252035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51937042609 + 1088208144 = 227897^2 + 32988^2 .
It is a cyclic number.
It is not a de Polignac number, because 53025250753 - 29 = 53025250241 is a prime.
It is a super-3 number, since 3×530252507533 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (53025250757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26512625376 + 26512625377.
It is an arithmetic number, because the mean of its divisors is an integer number (26512625377).
Almost surely, 253025250753 is an apocalyptic number.
It is an amenable number.
53025250753 is a deficient number, since it is larger than the sum of its proper divisors (1).
53025250753 is an equidigital number, since it uses as much as digits as its factorization.
53025250753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 157500, while the sum is 37.
The spelling of 53025250753 in words is "fifty-three billion, twenty-five million, two hundred fifty thousand, seven hundred fifty-three".
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