Base | Representation |
---|---|
bin | 100110100101001011110… |
… | …0011101010100000000001 |
3 | 200202220202121002222001011 |
4 | 1031022113203222200001 |
5 | 1143334041240231001 |
6 | 15135541050440521 |
7 | 1055044460216113 |
oct | 115122743524001 |
9 | 20686677088034 |
10 | 5302532352001 |
11 | 1764878304355 |
12 | 7177bb433141 |
13 | 2c604673b9c1 |
14 | 144902d5b3b3 |
15 | 92de739bd51 |
hex | 4d2978ea801 |
5302532352001 has 4 divisors (see below), whose sum is σ = 5305161274372. Its totient is φ = 5299903429632.
The previous prime is 5302532351983. The next prime is 5302532352049. The reversal of 5302532352001 is 1002532352035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4412436336400 + 890096015601 = 2100580^2 + 943449^2 .
It is a cyclic number.
It is not a de Polignac number, because 5302532352001 - 29 = 5302532351489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5302532350001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314458160 + ... + 1314462193.
It is an arithmetic number, because the mean of its divisors is an integer number (1326290318593).
Almost surely, 25302532352001 is an apocalyptic number.
It is an amenable number.
5302532352001 is a deficient number, since it is larger than the sum of its proper divisors (2628922371).
5302532352001 is a wasteful number, since it uses less digits than its factorization.
5302532352001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2628922370.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 5302532352001 in words is "five trillion, three hundred two billion, five hundred thirty-two million, three hundred fifty-two thousand, one".
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