Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010011110101100111001 |
3 | 200202220210011022101011101 |
4 | 1031022120002132230321 |
5 | 1143334100322231022 |
6 | 15135541535531401 |
7 | 1055044615662406 |
oct | 115123002365471 |
9 | 20686704271141 |
10 | 5302540430137 |
11 | 17648819215a5 |
12 | 717802089b61 |
13 | 2c6048309872 |
14 | 1449040612ad |
15 | 92de7e45627 |
hex | 4d29809eb39 |
5302540430137 has 2 divisors, whose sum is σ = 5302540430138. Its totient is φ = 5302540430136.
The previous prime is 5302540430101. The next prime is 5302540430153. The reversal of 5302540430137 is 7310340452035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3602635559721 + 1699904870416 = 1898061^2 + 1303804^2 .
It is a cyclic number.
It is not a de Polignac number, because 5302540430137 - 211 = 5302540428089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5302540430096 and 5302540430105.
It is not a weakly prime, because it can be changed into another prime (5302540430237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651270215068 + 2651270215069.
It is an arithmetic number, because the mean of its divisors is an integer number (2651270215069).
Almost surely, 25302540430137 is an apocalyptic number.
It is an amenable number.
5302540430137 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302540430137 is an equidigital number, since it uses as much as digits as its factorization.
5302540430137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 37.
The spelling of 5302540430137 in words is "five trillion, three hundred two billion, five hundred forty million, four hundred thirty thousand, one hundred thirty-seven".
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