Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010011111101100110111 |
3 | 200202220210011022120210000 |
4 | 1031022120002133230313 |
5 | 1143334100322343411 |
6 | 15135541540002343 |
7 | 1055044616010345 |
oct | 115123002375467 |
9 | 20686704276700 |
10 | 5302540434231 |
11 | 1764881924687 |
12 | 7178020903b3 |
13 | 2c604830b6a1 |
14 | 144904062995 |
15 | 92de7e46956 |
hex | 4d29809fb37 |
5302540434231 has 20 divisors (see below), whose sum is σ = 7921141961392. Its totient is φ = 3534998822208.
The previous prime is 5302540434221. The next prime is 5302540434277. The reversal of 5302540434231 is 1324340452035.
5302540434231 is a `hidden beast` number, since 5 + 3 + 0 + 2 + 540 + 43 + 42 + 31 = 666.
It is not a de Polignac number, because 5302540434231 - 29 = 5302540433719 is a prime.
It is a super-2 number, since 2×53025404342312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5302540434221) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 16980255 + ... + 17289711.
Almost surely, 25302540434231 is an apocalyptic number.
5302540434231 is a deficient number, since it is larger than the sum of its proper divisors (2618601527161).
5302540434231 is a wasteful number, since it uses less digits than its factorization.
5302540434231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 521012 (or 521003 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 36.
Adding to 5302540434231 its reverse (1324340452035), we get a palindrome (6626880886266).
The spelling of 5302540434231 in words is "five trillion, three hundred two billion, five hundred forty million, four hundred thirty-four thousand, two hundred thirty-one".
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