Base | Representation |
---|---|
bin | 110001011000100100… |
… | …001110101110001001 |
3 | 12001212102211111102221 |
4 | 301120210032232021 |
5 | 1332044012000131 |
6 | 40205400254041 |
7 | 3555010212403 |
oct | 613044165611 |
9 | 161772744387 |
10 | 53025500041 |
11 | 20540570008 |
12 | a33a171321 |
13 | 5000811c37 |
14 | 27d0493b73 |
15 | 15a52c4411 |
hex | c5890eb89 |
53025500041 has 2 divisors, whose sum is σ = 53025500042. Its totient is φ = 53025500040.
The previous prime is 53025499999. The next prime is 53025500057. The reversal of 53025500041 is 14000552035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30138348816 + 22887151225 = 173604^2 + 151285^2 .
It is a cyclic number.
It is not a de Polignac number, because 53025500041 - 27 = 53025499913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53025499979 and 53025500015.
It is not a weakly prime, because it can be changed into another prime (53025500081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26512750020 + 26512750021.
It is an arithmetic number, because the mean of its divisors is an integer number (26512750021).
Almost surely, 253025500041 is an apocalyptic number.
It is an amenable number.
53025500041 is a deficient number, since it is larger than the sum of its proper divisors (1).
53025500041 is an equidigital number, since it uses as much as digits as its factorization.
53025500041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 25.
The spelling of 53025500041 in words is "fifty-three billion, twenty-five million, five hundred thousand, forty-one".
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