Base | Representation |
---|---|
bin | 110001011000100101… |
… | …001001011101000101 |
3 | 12001212110021201110000 |
4 | 301120211021131011 |
5 | 1332044042144423 |
6 | 40205405351513 |
7 | 3555012233646 |
oct | 613045113505 |
9 | 161773251400 |
10 | 53025740613 |
11 | 2054071482a |
12 | a33a268599 |
13 | 50008975a1 |
14 | 27d05176cd |
15 | 15a5320843 |
hex | c58949745 |
53025740613 has 10 divisors (see below), whose sum is σ = 79211291654. Its totient is φ = 35350493688.
The previous prime is 53025740557. The next prime is 53025740639. The reversal of 53025740613 is 31604752035.
53025740613 is a `hidden beast` number, since 5 + 30 + 2 + 5 + 7 + 4 + 0 + 613 = 666.
It can be written as a sum of positive squares in only one way, i.e., 45025869249 + 7999871364 = 212193^2 + 89442^2 .
It is not a de Polignac number, because 53025740613 - 26 = 53025740549 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53025742613) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 327319306 + ... + 327319467.
Almost surely, 253025740613 is an apocalyptic number.
It is an amenable number.
53025740613 is a deficient number, since it is larger than the sum of its proper divisors (26185551041).
53025740613 is an equidigital number, since it uses as much as digits as its factorization.
53025740613 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 654638785 (or 654638776 counting only the distinct ones).
The product of its (nonzero) digits is 75600, while the sum is 36.
The spelling of 53025740613 in words is "fifty-three billion, twenty-five million, seven hundred forty thousand, six hundred thirteen".
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