Base | Representation |
---|---|
bin | 11000000111010010010001… |
… | …11100110010001010010011 |
3 | 20221202022200010221200102012 |
4 | 30003221020330302022103 |
5 | 23422243032333130232 |
6 | 304440114513413135 |
7 | 14112031525130660 |
oct | 1403511074621223 |
9 | 227668603850365 |
10 | 53026890130067 |
11 | 1599463a085557 |
12 | 5b44b7226a1ab |
13 | 2378550245639 |
14 | d1472d902a67 |
15 | 61e53ee849b2 |
hex | 303a48f32293 |
53026890130067 has 8 divisors (see below), whose sum is σ = 60602215161696. Its totient is φ = 45451578851712.
The previous prime is 53026890130063. The next prime is 53026890130099. The reversal of 53026890130067 is 76003109862035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53026890130067 - 22 = 53026890130063 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53026890129997 and 53026890130024.
It is not an unprimeable number, because it can be changed into a prime (53026890130063) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6893333 + ... + 12392409.
It is an arithmetic number, because the mean of its divisors is an integer number (7575276895212).
Almost surely, 253026890130067 is an apocalyptic number.
53026890130067 is a deficient number, since it is larger than the sum of its proper divisors (7575325031629).
53026890130067 is a wasteful number, since it uses less digits than its factorization.
53026890130067 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6876637.
The product of its (nonzero) digits is 1632960, while the sum is 50.
The spelling of 53026890130067 in words is "fifty-three trillion, twenty-six billion, eight hundred ninety million, one hundred thirty thousand, sixty-seven".
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