Base | Representation |
---|---|
bin | 11000000111011000011101… |
… | …00011111011010001000011 |
3 | 20221202122020012102001102221 |
4 | 30003230032203323101003 |
5 | 23422321330102040111 |
6 | 304441423505351511 |
7 | 14112206633256625 |
oct | 1403541643732103 |
9 | 227678205361387 |
10 | 53030205502531 |
11 | 15995a905699a4 |
12 | 5b45738638597 |
13 | 237895b07a9aa |
14 | d14965d60c15 |
15 | 61e686072371 |
hex | 303b0e8fb443 |
53030205502531 has 2 divisors, whose sum is σ = 53030205502532. Its totient is φ = 53030205502530.
The previous prime is 53030205502507. The next prime is 53030205502601. The reversal of 53030205502531 is 13520550203035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53030205502531 - 211 = 53030205500483 is a prime.
It is a super-2 number, since 2×530302055025312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53030205502931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26515102751265 + 26515102751266.
It is an arithmetic number, because the mean of its divisors is an integer number (26515102751266).
Almost surely, 253030205502531 is an apocalyptic number.
53030205502531 is a deficient number, since it is larger than the sum of its proper divisors (1).
53030205502531 is an equidigital number, since it uses as much as digits as its factorization.
53030205502531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67500, while the sum is 34.
Adding to 53030205502531 its reverse (13520550203035), we get a palindrome (66550755705566).
The spelling of 53030205502531 in words is "fifty-three trillion, thirty billion, two hundred five million, five hundred two thousand, five hundred thirty-one".
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