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53030250000003 = 335814936260821
BaseRepresentation
bin11000000111011000100010…
…01101101010111010000011
320221202122100022010202111110
430003230101031222322003
523422321423000000003
6304441432135214403
714112211013426103
oct1403542115527203
9227678308122443
1053030250000003
11159960036a1571
125b4574b517403
13237896735a663
14d1496bc25203
1561e689e11a03
hex303b1136ae83

53030250000003 has 8 divisors (see below), whose sum is σ = 70726745057616. Its totient is φ = 35343627471200.

The previous prime is 53030249999989. The next prime is 53030250000023. The reversal of 53030250000003 is 30000005203035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53030250000003 - 212 = 53030249995907 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53030250000023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2468119668 + ... + 2468141153.

It is an arithmetic number, because the mean of its divisors is an integer number (8840843132202).

Almost surely, 253030250000003 is an apocalyptic number.

53030250000003 is a deficient number, since it is larger than the sum of its proper divisors (17696495057613).

53030250000003 is a wasteful number, since it uses less digits than its factorization.

53030250000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4936264405.

The product of its (nonzero) digits is 1350, while the sum is 21.

Adding to 53030250000003 its reverse (30000005203035), we get a palindrome (83030255203038).

The spelling of 53030250000003 in words is "fifty-three trillion, thirty billion, two hundred fifty million, three", and thus it is an aban number.

Divisors: 1 3 3581 10743 4936260821 14808782463 17676750000001 53030250000003