Base | Representation |
---|---|
bin | 11000000111011000100010… |
… | …01101101010111010000011 |
3 | 20221202122100022010202111110 |
4 | 30003230101031222322003 |
5 | 23422321423000000003 |
6 | 304441432135214403 |
7 | 14112211013426103 |
oct | 1403542115527203 |
9 | 227678308122443 |
10 | 53030250000003 |
11 | 159960036a1571 |
12 | 5b4574b517403 |
13 | 237896735a663 |
14 | d1496bc25203 |
15 | 61e689e11a03 |
hex | 303b1136ae83 |
53030250000003 has 8 divisors (see below), whose sum is σ = 70726745057616. Its totient is φ = 35343627471200.
The previous prime is 53030249999989. The next prime is 53030250000023. The reversal of 53030250000003 is 30000005203035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53030250000003 - 212 = 53030249995907 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53030250000023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2468119668 + ... + 2468141153.
It is an arithmetic number, because the mean of its divisors is an integer number (8840843132202).
Almost surely, 253030250000003 is an apocalyptic number.
53030250000003 is a deficient number, since it is larger than the sum of its proper divisors (17696495057613).
53030250000003 is a wasteful number, since it uses less digits than its factorization.
53030250000003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4936264405.
The product of its (nonzero) digits is 1350, while the sum is 21.
Adding to 53030250000003 its reverse (30000005203035), we get a palindrome (83030255203038).
The spelling of 53030250000003 in words is "fifty-three trillion, thirty billion, two hundred fifty million, three", and thus it is an aban number.
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