Base | Representation |
---|---|
bin | 110001011000111011… |
… | …001000010110010001 |
3 | 12001212212010111021222 |
4 | 301120323020112101 |
5 | 1332102031100444 |
6 | 40210133054425 |
7 | 3555112224434 |
oct | 613073102621 |
9 | 161785114258 |
10 | 53031503249 |
11 | 205439a033a |
12 | a340187415 |
13 | 5001b3452a |
14 | 27d11b781b |
15 | 15a5aaceee |
hex | c58ec8591 |
53031503249 has 2 divisors, whose sum is σ = 53031503250. Its totient is φ = 53031503248.
The previous prime is 53031503209. The next prime is 53031503267. The reversal of 53031503249 is 94230513035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52995262849 + 36240400 = 230207^2 + 6020^2 .
It is a cyclic number.
It is not a de Polignac number, because 53031503249 - 216 = 53031437713 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (53031503209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26515751624 + 26515751625.
It is an arithmetic number, because the mean of its divisors is an integer number (26515751625).
Almost surely, 253031503249 is an apocalyptic number.
It is an amenable number.
53031503249 is a deficient number, since it is larger than the sum of its proper divisors (1).
53031503249 is an equidigital number, since it uses as much as digits as its factorization.
53031503249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 35.
The spelling of 53031503249 in words is "fifty-three billion, thirty-one million, five hundred three thousand, two hundred forty-nine".
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