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530320335473 is a prime number
BaseRepresentation
bin1111011011110011000…
…11100010001001110001
31212200211221021100021102
413231321203202021301
532142044001213343
61043343101134145
753212555322015
oct7557143421161
91780757240242
10530320335473
111949a9005295
128694325a355
133b0169b0996
141b94c016545
15dbdc9363b8
hex7b798e2271

530320335473 has 2 divisors, whose sum is σ = 530320335474. Its totient is φ = 530320335472.

The previous prime is 530320335437. The next prime is 530320335541. The reversal of 530320335473 is 374533023035.

Together with previous prime (530320335437) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 409999457344 + 120320878129 = 640312^2 + 346873^2 .

It is a cyclic number.

It is not a de Polignac number, because 530320335473 - 232 = 526025368177 is a prime.

It is not a weakly prime, because it can be changed into another prime (530320335173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265160167736 + 265160167737.

It is an arithmetic number, because the mean of its divisors is an integer number (265160167737).

Almost surely, 2530320335473 is an apocalyptic number.

It is an amenable number.

530320335473 is a deficient number, since it is larger than the sum of its proper divisors (1).

530320335473 is an equidigital number, since it uses as much as digits as its factorization.

530320335473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 340200, while the sum is 38.

The spelling of 530320335473 in words is "five hundred thirty billion, three hundred twenty million, three hundred thirty-five thousand, four hundred seventy-three".