Base | Representation |
---|---|
bin | 1111011011110011010… |
… | …11011101101000101001 |
3 | 1212200212002011221122101 |
4 | 13231321223131220221 |
5 | 32142100014222441 |
6 | 1043343213453401 |
7 | 53212612100143 |
oct | 7557153355051 |
9 | 1780762157571 |
10 | 530322414121 |
11 | 1949aa1a4a85 |
12 | 86943aa1261 |
13 | 3b01725ab56 |
14 | 1b94c3d7c93 |
15 | dbdcbe7231 |
hex | 7b79adda29 |
530322414121 has 2 divisors, whose sum is σ = 530322414122. Its totient is φ = 530322414120.
The previous prime is 530322414007. The next prime is 530322414161. The reversal of 530322414121 is 121414223035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 521233461225 + 9088952896 = 721965^2 + 95336^2 .
It is a cyclic number.
It is not a de Polignac number, because 530322414121 - 233 = 521732479529 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 530322414121.
It is not a weakly prime, because it can be changed into another prime (530322414161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265161207060 + 265161207061.
It is an arithmetic number, because the mean of its divisors is an integer number (265161207061).
Almost surely, 2530322414121 is an apocalyptic number.
It is an amenable number.
530322414121 is a deficient number, since it is larger than the sum of its proper divisors (1).
530322414121 is an equidigital number, since it uses as much as digits as its factorization.
530322414121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 530322414121 its reverse (121414223035), we get a palindrome (651736637156).
The spelling of 530322414121 in words is "five hundred thirty billion, three hundred twenty-two million, four hundred fourteen thousand, one hundred twenty-one".
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