Base | Representation |
---|---|
bin | 1111011011110100011… |
… | …01010111110110010001 |
3 | 1212200212200220120022201 |
4 | 13231322031113312101 |
5 | 32142104303201223 |
6 | 1043344132203201 |
7 | 53213050462150 |
oct | 7557215276621 |
9 | 1780780816281 |
10 | 530331303313 |
11 | 194a04216619 |
12 | 86946a69501 |
13 | 3b019050c26 |
14 | 1b94d66d597 |
15 | dbdd8a0ead |
hex | 7b7a357d91 |
530331303313 has 4 divisors (see below), whose sum is σ = 606092918080. Its totient is φ = 454569688548.
The previous prime is 530331303301. The next prime is 530331303343. The reversal of 530331303313 is 313303133035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530331303313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530331303343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37880807373 + ... + 37880807386.
It is an arithmetic number, because the mean of its divisors is an integer number (151523229520).
Almost surely, 2530331303313 is an apocalyptic number.
It is an amenable number.
530331303313 is a deficient number, since it is larger than the sum of its proper divisors (75761614767).
530331303313 is an equidigital number, since it uses as much as digits as its factorization.
530331303313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75761614766.
The product of its (nonzero) digits is 10935, while the sum is 28.
Adding to 530331303313 its reverse (313303133035), we get a palindrome (843634436348).
The spelling of 530331303313 in words is "five hundred thirty billion, three hundred thirty-one million, three hundred three thousand, three hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •