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530331531043 = 1074956369449
BaseRepresentation
bin1111011011110100011…
…10001111011100100011
31212200212201100010201011
413231322032033130203
532142104332443133
61043344141121351
753213052431116
oct7557216173443
91780781303634
10530331531043
11194a04361726
1286946b59257
133b019100792
141b94d6cc57d
15dbdd8e86cd
hex7b7a38f723

530331531043 has 4 divisors (see below), whose sum is σ = 535287900600. Its totient is φ = 525375161488.

The previous prime is 530331531007. The next prime is 530331531053. The reversal of 530331531043 is 340135133035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530331531043 is a prime.

It is a super-3 number, since 3×5303315310433 (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530331530996 and 530331531014.

It is not an unprimeable number, because it can be changed into a prime (530331531053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2478184618 + ... + 2478184831.

It is an arithmetic number, because the mean of its divisors is an integer number (133821975150).

Almost surely, 2530331531043 is an apocalyptic number.

530331531043 is a deficient number, since it is larger than the sum of its proper divisors (4956369557).

530331531043 is a wasteful number, since it uses less digits than its factorization.

530331531043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4956369556.

The product of its (nonzero) digits is 24300, while the sum is 31.

Adding to 530331531043 its reverse (340135133035), we get a palindrome (870466664078).

The spelling of 530331531043 in words is "five hundred thirty billion, three hundred thirty-one million, five hundred thirty-one thousand, forty-three".

Divisors: 1 107 4956369449 530331531043