Base | Representation |
---|---|
bin | 100110100101100011101… |
… | …0110111110101001101011 |
3 | 200202222211111011211012102 |
4 | 1031023013112332221223 |
5 | 1143342212042124120 |
6 | 15140152420004015 |
7 | 1055103366023204 |
oct | 115130726765153 |
9 | 20688744154172 |
10 | 5303334333035 |
11 | 1765149a785a2 |
12 | 7179a3b3060b |
13 | 2c61439364ab |
14 | 14497b6805ab |
15 | 92e429b5d75 |
hex | 4d2c75bea6b |
5303334333035 has 16 divisors (see below), whose sum is σ = 6433711415040. Its totient is φ = 4196295577440.
The previous prime is 5303334333019. The next prime is 5303334333043.
5303334333035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5303334333035 - 24 = 5303334333019 is a prime.
It is a super-2 number, since 2×53033343330352 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5303334333035.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5931125 + ... + 6766454.
It is an arithmetic number, because the mean of its divisors is an integer number (402106963440).
Almost surely, 25303334333035 is an apocalyptic number.
5303334333035 is a deficient number, since it is larger than the sum of its proper divisors (1130377082005).
5303334333035 is a wasteful number, since it uses less digits than its factorization.
5303334333035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12698498.
The product of its (nonzero) digits is 656100, while the sum is 38.
The spelling of 5303334333035 in words is "five trillion, three hundred three billion, three hundred thirty-four million, three hundred thirty-three thousand, thirty-five".
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