Base | Representation |
---|---|
bin | 100110100101100101101… |
… | …1101001110110111001001 |
3 | 200210000000021112120220022 |
4 | 1031023023131032313021 |
5 | 1143342332142044121 |
6 | 15140203313310225 |
7 | 1055105162254103 |
oct | 115131335166711 |
9 | 20700007476808 |
10 | 5303403081161 |
11 | 1765184864029 |
12 | 717a02b65375 |
13 | 2c6154c57263 |
14 | 144986858573 |
15 | 92e48a45aab |
hex | 4d2cb74edc9 |
5303403081161 has 2 divisors, whose sum is σ = 5303403081162. Its totient is φ = 5303403081160.
The previous prime is 5303403081127. The next prime is 5303403081167. The reversal of 5303403081161 is 1611803043035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4389314114761 + 914088966400 = 2095069^2 + 956080^2 .
It is a cyclic number.
It is not a de Polignac number, because 5303403081161 - 238 = 5028525174217 is a prime.
It is not a weakly prime, because it can be changed into another prime (5303403081167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651701540580 + 2651701540581.
It is an arithmetic number, because the mean of its divisors is an integer number (2651701540581).
Almost surely, 25303403081161 is an apocalyptic number.
It is an amenable number.
5303403081161 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303403081161 is an equidigital number, since it uses as much as digits as its factorization.
5303403081161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 5303403081161 in words is "five trillion, three hundred three billion, four hundred three million, eighty-one thousand, one hundred sixty-one".
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