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5303424115450 = 252106068482309
BaseRepresentation
bin100110100101100110010…
…1101011110001011111010
3200210000001202010020112001
41031023030231132023322
51143342403033143300
615140205344211214
71055105536121416
oct115131455361372
920700052106461
105303424115450
11176519572043a
12717a0a009b0a
132c6159410396
14144989571d46
1592e4a7ed16a
hex4d2ccb5e2fa

5303424115450 has 12 divisors (see below), whose sum is σ = 9864368854830. Its totient is φ = 2121369646160.

The previous prime is 5303424115397. The next prime is 5303424115469. The reversal of 5303424115450 is 545114243035.

It can be written as a sum of positive squares in 3 ways, for example, as 4194103298401 + 1109320817049 = 2047951^2 + 1053243^2 .

It is a super-2 number, since 2×53034241154502 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 53034241105 + ... + 53034241204.

Almost surely, 25303424115450 is an apocalyptic number.

5303424115450 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

5303424115450 is a deficient number, since it is larger than the sum of its proper divisors (4560944739380).

5303424115450 is a wasteful number, since it uses less digits than its factorization.

5303424115450 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106068482321 (or 106068482316 counting only the distinct ones).

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 5303424115450 its reverse (545114243035), we get a palindrome (5848538358485).

The spelling of 5303424115450 in words is "five trillion, three hundred three billion, four hundred twenty-four million, one hundred fifteen thousand, four hundred fifty".

Divisors: 1 2 5 10 25 50 106068482309 212136964618 530342411545 1060684823090 2651712057725 5303424115450