Base | Representation |
---|---|
bin | 100110100101100110010… |
… | …1101011110001011111010 |
3 | 200210000001202010020112001 |
4 | 1031023030231132023322 |
5 | 1143342403033143300 |
6 | 15140205344211214 |
7 | 1055105536121416 |
oct | 115131455361372 |
9 | 20700052106461 |
10 | 5303424115450 |
11 | 176519572043a |
12 | 717a0a009b0a |
13 | 2c6159410396 |
14 | 144989571d46 |
15 | 92e4a7ed16a |
hex | 4d2ccb5e2fa |
5303424115450 has 12 divisors (see below), whose sum is σ = 9864368854830. Its totient is φ = 2121369646160.
The previous prime is 5303424115397. The next prime is 5303424115469. The reversal of 5303424115450 is 545114243035.
It can be written as a sum of positive squares in 3 ways, for example, as 4194103298401 + 1109320817049 = 2047951^2 + 1053243^2 .
It is a super-2 number, since 2×53034241154502 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 53034241105 + ... + 53034241204.
Almost surely, 25303424115450 is an apocalyptic number.
5303424115450 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5303424115450 is a deficient number, since it is larger than the sum of its proper divisors (4560944739380).
5303424115450 is a wasteful number, since it uses less digits than its factorization.
5303424115450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106068482321 (or 106068482316 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 5303424115450 its reverse (545114243035), we get a palindrome (5848538358485).
The spelling of 5303424115450 in words is "five trillion, three hundred three billion, four hundred twenty-four million, one hundred fifteen thousand, four hundred fifty".
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