Base | Representation |
---|---|
bin | 111100010010110001101110… |
… | …1111101110011111000011011 |
3 | 2120112210121110111212111112002 |
4 | 1320211203131331303320123 |
5 | 1024003143143113144412 |
6 | 5115541415320511215 |
7 | 216465153234265433 |
oct | 17045433575637033 |
9 | 2515717414774462 |
10 | 530346285678107 |
11 | 143a91662191158 |
12 | 4b5947b601b50b |
13 | 199c0595004b42 |
14 | 94d6c7bc4b2c3 |
15 | 414a7cd5d5dc2 |
hex | 1e258ddf73e1b |
530346285678107 has 2 divisors, whose sum is σ = 530346285678108. Its totient is φ = 530346285678106.
The previous prime is 530346285678103. The next prime is 530346285678193. The reversal of 530346285678107 is 701876582643035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530346285678107 - 22 = 530346285678103 is a prime.
It is not a weakly prime, because it can be changed into another prime (530346285678103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265173142839053 + 265173142839054.
It is an arithmetic number, because the mean of its divisors is an integer number (265173142839054).
Almost surely, 2530346285678107 is an apocalyptic number.
530346285678107 is a deficient number, since it is larger than the sum of its proper divisors (1).
530346285678107 is an equidigital number, since it uses as much as digits as its factorization.
530346285678107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 203212800, while the sum is 65.
The spelling of 530346285678107 in words is "five hundred thirty trillion, three hundred forty-six billion, two hundred eighty-five million, six hundred seventy-eight thousand, one hundred seven".
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