Base | Representation |
---|---|
bin | 111100010010110011111100… |
… | …0010101101100011110001100 |
3 | 2120112211001200200012012000022 |
4 | 1320211213320111230132030 |
5 | 1024003232343404122444 |
6 | 5115543521352321312 |
7 | 216465411520652312 |
oct | 17045477025543614 |
9 | 2515731620165008 |
10 | 530351023114124 |
11 | 143a93673363a33 |
12 | 4b5956b86a3238 |
13 | 199c0b6b642414 |
14 | 94d71ab0c20b2 |
15 | 414a9a94759ee |
hex | 1e259f856c78c |
530351023114124 has 12 divisors (see below), whose sum is σ = 931997613842400. Its totient is φ = 264065990587728.
The previous prime is 530351023114097. The next prime is 530351023114151. The reversal of 530351023114124 is 421411320153035.
It is an interprime number because it is at equal distance from previous prime (530351023114097) and next prime (530351023114151).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 277380241259 + ... + 277380243170.
It is an arithmetic number, because the mean of its divisors is an integer number (77666467820200).
Almost surely, 2530351023114124 is an apocalyptic number.
It is an amenable number.
530351023114124 is a deficient number, since it is larger than the sum of its proper divisors (401646590728276).
530351023114124 is a wasteful number, since it uses less digits than its factorization.
530351023114124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 554760484672 (or 554760484670 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 530351023114124 its reverse (421411320153035), we get a palindrome (951762343267159).
The spelling of 530351023114124 in words is "five hundred thirty trillion, three hundred fifty-one billion, twenty-three million, one hundred fourteen thousand, one hundred twenty-four".
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