Base | Representation |
---|---|
bin | 1111011011110110110… |
… | …10010000111010000011 |
3 | 1212200221002211122001121 |
4 | 13231323122100322003 |
5 | 32142124433204341 |
6 | 1043350132213111 |
7 | 53213414013004 |
oct | 7557332207203 |
9 | 1780832748047 |
10 | 530351459971 |
11 | 194a14633613 |
12 | 8695176a197 |
13 | 3b02028a748 |
14 | 1b9521d91ab |
15 | dbe05334d1 |
hex | 7b7b690e83 |
530351459971 has 2 divisors, whose sum is σ = 530351459972. Its totient is φ = 530351459970.
The previous prime is 530351459929. The next prime is 530351459977. The reversal of 530351459971 is 179954153035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530351459971 - 29 = 530351459459 is a prime.
It is not a weakly prime, because it can be changed into another prime (530351459977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265175729985 + 265175729986.
It is an arithmetic number, because the mean of its divisors is an integer number (265175729986).
Almost surely, 2530351459971 is an apocalyptic number.
530351459971 is a deficient number, since it is larger than the sum of its proper divisors (1).
530351459971 is an equidigital number, since it uses as much as digits as its factorization.
530351459971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2551500, while the sum is 52.
The spelling of 530351459971 in words is "five hundred thirty billion, three hundred fifty-one million, four hundred fifty-nine thousand, nine hundred seventy-one".
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