Base | Representation |
---|---|
bin | 1111011011110111001… |
… | …00011111100011111001 |
3 | 1212200221021212212100000 |
4 | 13231323210133203321 |
5 | 32142131130011213 |
6 | 1043350305503213 |
7 | 53213445551454 |
oct | 7557344374371 |
9 | 1780837785300 |
10 | 530354141433 |
11 | 194a160a51a6 |
12 | 86952641b09 |
13 | 3b0209b90cc |
14 | 1b9526d649b |
15 | dbe08b2c73 |
hex | 7b7b91f8f9 |
530354141433 has 24 divisors (see below), whose sum is σ = 803366272800. Its totient is φ = 349596723168.
The previous prime is 530354141423. The next prime is 530354141459. The reversal of 530354141433 is 334141453035.
530354141433 is a `hidden beast` number, since 5 + 30 + 3 + 54 + 141 + 433 = 666.
It is not a de Polignac number, because 530354141433 - 216 = 530354075897 is a prime.
It is not an unprimeable number, because it can be changed into a prime (530354141423) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12239763 + ... + 12283016.
It is an arithmetic number, because the mean of its divisors is an integer number (33473594700).
Almost surely, 2530354141433 is an apocalyptic number.
It is an amenable number.
530354141433 is a deficient number, since it is larger than the sum of its proper divisors (273012131367).
530354141433 is an equidigital number, since it uses as much as digits as its factorization.
530354141433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24522883 (or 24522871 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 36.
Adding to 530354141433 its reverse (334141453035), we get a palindrome (864495594468).
The spelling of 530354141433 in words is "five hundred thirty billion, three hundred fifty-four million, one hundred forty-one thousand, four hundred thirty-three".
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