Base | Representation |
---|---|
bin | 100110100101101001111… |
… | …0011001001101110111001 |
3 | 200210000101000220111021000 |
4 | 1031023103303021232321 |
5 | 1143343124004420144 |
6 | 15140225233235213 |
7 | 1055111512034064 |
oct | 115132363115671 |
9 | 20700330814230 |
10 | 5303543045049 |
11 | 1765246870a67 |
12 | 717a41a02b09 |
13 | 2c6177c51022 |
14 | 14499b28d8db |
15 | 92e55e91769 |
hex | 4d2d3cc9bb9 |
5303543045049 has 16 divisors (see below), whose sum is σ = 8319283208640. Its totient is φ = 3327713282880.
The previous prime is 5303543045011. The next prime is 5303543045051. The reversal of 5303543045049 is 9405403453035.
5303543045049 is a `hidden beast` number, since 53 + 0 + 3 + 543 + 0 + 4 + 50 + 4 + 9 = 666.
It is not a de Polignac number, because 5303543045049 - 29 = 5303543044537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5303543044995 and 5303543045013.
It is not an unprimeable number, because it can be changed into a prime (5303543045089) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5777279547 + ... + 5777280464.
It is an arithmetic number, because the mean of its divisors is an integer number (519955200540).
Almost surely, 25303543045049 is an apocalyptic number.
It is an amenable number.
5303543045049 is a deficient number, since it is larger than the sum of its proper divisors (3015740163591).
5303543045049 is a wasteful number, since it uses less digits than its factorization.
5303543045049 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11554560037 (or 11554560031 counting only the distinct ones).
The product of its (nonzero) digits is 1944000, while the sum is 45.
The spelling of 5303543045049 in words is "five trillion, three hundred three billion, five hundred forty-three million, forty-five thousand, forty-nine".
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