Base | Representation |
---|---|
bin | 110001011001001010… |
… | …100101101010111001 |
3 | 12001220010202100221211 |
4 | 301121022211222321 |
5 | 1332104100234023 |
6 | 40210400003121 |
7 | 3555161532553 |
oct | 613112455271 |
9 | 161803670854 |
10 | 53035555513 |
11 | 20546208916 |
12 | a3416004a1 |
13 | 5002922b15 |
14 | 27d19504d3 |
15 | 15a610da0d |
hex | c592a5ab9 |
53035555513 has 4 divisors (see below), whose sum is σ = 55826900560. Its totient is φ = 50244210468.
The previous prime is 53035555493. The next prime is 53035555543. The reversal of 53035555513 is 31555553035.
53035555513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53035555513 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53035555543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1395672495 + ... + 1395672532.
It is an arithmetic number, because the mean of its divisors is an integer number (13956725140).
Almost surely, 253035555513 is an apocalyptic number.
It is an amenable number.
53035555513 is a deficient number, since it is larger than the sum of its proper divisors (2791345047).
53035555513 is a wasteful number, since it uses less digits than its factorization.
53035555513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2791345046.
The product of its (nonzero) digits is 421875, while the sum is 40.
The spelling of 53035555513 in words is "fifty-three billion, thirty-five million, five hundred fifty-five thousand, five hundred thirteen".
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