Base | Representation |
---|---|
bin | 11000000111101011100001… |
… | …11000100011000011100001 |
3 | 20221210121122210211221020200 |
4 | 30003311300320203003201 |
5 | 23423003312410311040 |
6 | 304450235525455413 |
7 | 14113021446533535 |
oct | 1403656070430341 |
9 | 227717583757220 |
10 | 53040445010145 |
11 | 1599a3654a058a |
12 | 5b47715871569 |
13 | 2379900575b38 |
14 | d15257c2bbc5 |
15 | 61ea84e90630 |
hex | 303d70e230e1 |
53040445010145 has 96 divisors (see below), whose sum is σ = 97311154187520. Its totient is φ = 26651459911680.
The previous prime is 53040445010143. The next prime is 53040445010149. The reversal of 53040445010145 is 54101054404035.
53040445010145 is a `hidden beast` number, since 5 + 3 + 0 + 4 + 0 + 4 + 4 + 501 + 0 + 145 = 666.
It is not a de Polignac number, because 53040445010145 - 21 = 53040445010143 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53040445010143) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 114906529 + ... + 115367201.
It is an arithmetic number, because the mean of its divisors is an integer number (1013657856120).
Almost surely, 253040445010145 is an apocalyptic number.
It is an amenable number.
53040445010145 is a deficient number, since it is larger than the sum of its proper divisors (44270709177375).
53040445010145 is a wasteful number, since it uses less digits than its factorization.
53040445010145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 461447 (or 461444 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 36.
The spelling of 53040445010145 in words is "fifty-three trillion, forty billion, four hundred forty-five million, ten thousand, one hundred forty-five".
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