Base | Representation |
---|---|
bin | 1111011011111101001… |
… | …00110010011100100001 |
3 | 1212201001210201220111000 |
4 | 13231332210302130201 |
5 | 32142232031103213 |
6 | 1043355310142213 |
7 | 53214630201462 |
oct | 7557644623441 |
9 | 1781053656430 |
10 | 530404550433 |
11 | 194a415a522a |
12 | 869674b1969 |
13 | 3b02b288714 |
14 | 1b959298d69 |
15 | dbe501dc73 |
hex | 7b7e932721 |
530404550433 has 8 divisors (see below), whose sum is σ = 785784519200. Its totient is φ = 353603033604.
The previous prime is 530404550413. The next prime is 530404550491. The reversal of 530404550433 is 334055404035.
530404550433 is a `hidden beast` number, since 5 + 30 + 40 + 4 + 550 + 4 + 33 = 666.
It is not a de Polignac number, because 530404550433 - 233 = 521814615841 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (530404550413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9822306463 + ... + 9822306516.
It is an arithmetic number, because the mean of its divisors is an integer number (98223064900).
Almost surely, 2530404550433 is an apocalyptic number.
It is an amenable number.
530404550433 is a deficient number, since it is larger than the sum of its proper divisors (255379968767).
530404550433 is a wasteful number, since it uses less digits than its factorization.
530404550433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19644612988 (or 19644612982 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 36.
Adding to 530404550433 its reverse (334055404035), we get a palindrome (864459954468).
The spelling of 530404550433 in words is "five hundred thirty billion, four hundred four million, five hundred fifty thousand, four hundred thirty-three".
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