Base | Representation |
---|---|
bin | 111100010011011010001101… |
… | …1001011111000111101110010 |
3 | 2120120002220211120022112110201 |
4 | 1320212310123023320331302 |
5 | 1024011104204301000132 |
6 | 5120045353104145414 |
7 | 216504351323014042 |
oct | 17046643313707562 |
9 | 2516086746275421 |
10 | 530433212125042 |
11 | 144015509974346 |
12 | 4b5a961560826a |
13 | 199c883912ba65 |
14 | 94db166877722 |
15 | 414cbb9be02e7 |
hex | 1e26d1b2f8f72 |
530433212125042 has 16 divisors (see below), whose sum is σ = 830245814904960. Its totient is φ = 253684677333472.
The previous prime is 530433212125013. The next prime is 530433212125129. The reversal of 530433212125042 is 240521212334035.
It is a junction number, because it is equal to n+sod(n) for n = 530433212124992 and 530433212125010.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2116918 + ... + 32639665.
It is an arithmetic number, because the mean of its divisors is an integer number (51890363431560).
Almost surely, 2530433212125042 is an apocalyptic number.
530433212125042 is a deficient number, since it is larger than the sum of its proper divisors (299812602779918).
530433212125042 is a wasteful number, since it uses less digits than its factorization.
530433212125042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35088377.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 530433212125042 its reverse (240521212334035), we get a palindrome (770954424459077).
The spelling of 530433212125042 in words is "five hundred thirty trillion, four hundred thirty-three billion, two hundred twelve million, one hundred twenty-five thousand, forty-two".
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