Base | Representation |
---|---|
bin | 100110100110000100000… |
… | …1100000011110011011001 |
3 | 200210002122021210111111122 |
4 | 1031030020030003303121 |
5 | 1143401424012131333 |
6 | 15140452352135025 |
7 | 1055142343656446 |
oct | 115141014036331 |
9 | 20702567714448 |
10 | 5304421989593 |
11 | 1765657a22011 |
12 | 718048237475 |
13 | 2c6288084a5c |
14 | 144a41cc89cd |
15 | 92ea820e798 |
hex | 4d308303cd9 |
5304421989593 has 2 divisors, whose sum is σ = 5304421989594. Its totient is φ = 5304421989592.
The previous prime is 5304421989541. The next prime is 5304421989611. The reversal of 5304421989593 is 3959891244035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5191416427024 + 113005562569 = 2278468^2 + 336163^2 .
It is a cyclic number.
It is not a de Polignac number, because 5304421989593 - 214 = 5304421973209 is a prime.
It is not a weakly prime, because it can be changed into another prime (5304421985593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652210994796 + 2652210994797.
It is an arithmetic number, because the mean of its divisors is an integer number (2652210994797).
Almost surely, 25304421989593 is an apocalyptic number.
It is an amenable number.
5304421989593 is a deficient number, since it is larger than the sum of its proper divisors (1).
5304421989593 is an equidigital number, since it uses as much as digits as its factorization.
5304421989593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41990400, while the sum is 62.
The spelling of 5304421989593 in words is "five trillion, three hundred four billion, four hundred twenty-one million, nine hundred eighty-nine thousand, five hundred ninety-three".
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