Base | Representation |
---|---|
bin | 100110100110000100001… |
… | …0101101110101011101001 |
3 | 200210002122110120021202212 |
4 | 1031030020111232223221 |
5 | 1143401430134241041 |
6 | 15140452522334505 |
7 | 1055142404345063 |
oct | 115141025565351 |
9 | 20702573507685 |
10 | 5304424524521 |
11 | 17656593a35a1 |
12 | 71804905a435 |
13 | 2c6288761805 |
14 | 144a42388733 |
15 | 92ea85608eb |
hex | 4d30856eae9 |
5304424524521 has 4 divisors (see below), whose sum is σ = 5304432807552. Its totient is φ = 5304416241492.
The previous prime is 5304424524517. The next prime is 5304424524569. The reversal of 5304424524521 is 1254254244035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5304424524521 - 22 = 5304424524517 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5304424524571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3092321 + ... + 4491246.
It is an arithmetic number, because the mean of its divisors is an integer number (1326108201888).
Almost surely, 25304424524521 is an apocalyptic number.
It is an amenable number.
5304424524521 is a deficient number, since it is larger than the sum of its proper divisors (8283031).
5304424524521 is an equidigital number, since it uses as much as digits as its factorization.
5304424524521 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8283030.
The product of its (nonzero) digits is 768000, while the sum is 41.
Adding to 5304424524521 its reverse (1254254244035), we get a palindrome (6558678768556).
The spelling of 5304424524521 in words is "five trillion, three hundred four billion, four hundred twenty-four million, five hundred twenty-four thousand, five hundred twenty-one".
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