Base | Representation |
---|---|
bin | 11000000111110010110010… |
… | …00111101110101110011111 |
3 | 20221210222201100102011220202 |
4 | 30003321121013232232133 |
5 | 23423034302333213343 |
6 | 304452122312534115 |
7 | 14113220140511513 |
oct | 1403713107565637 |
9 | 227728640364822 |
10 | 53044341304223 |
11 | 159a0a84891a35 |
12 | 5b484226b133b |
13 | 237a0a1856ca9 |
14 | d155074a8143 |
15 | 61ec1207cdb8 |
hex | 303e591eeb9f |
53044341304223 has 16 divisors (see below), whose sum is σ = 55980356536800. Its totient is φ = 50188361758080.
The previous prime is 53044341304211. The next prime is 53044341304243. The reversal of 53044341304223 is 32240314344035.
It is a cyclic number.
It is not a de Polignac number, because 53044341304223 - 212 = 53044341300127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53044341304243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55259261 + ... + 56210982.
It is an arithmetic number, because the mean of its divisors is an integer number (3498772283550).
Almost surely, 253044341304223 is an apocalyptic number.
53044341304223 is a deficient number, since it is larger than the sum of its proper divisors (2936015232577).
53044341304223 is a wasteful number, since it uses less digits than its factorization.
53044341304223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 111470602.
The product of its (nonzero) digits is 414720, while the sum is 38.
Adding to 53044341304223 its reverse (32240314344035), we get a palindrome (85284655648258).
The spelling of 53044341304223 in words is "fifty-three trillion, forty-four billion, three hundred forty-one million, three hundred four thousand, two hundred twenty-three".
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