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53044444033 = 77577777719
BaseRepresentation
bin110001011001101100…
…011111101110000001
312001220202110221201021
4301121230133232001
51332113334202113
640211314305441
73555330222610
oct613154375601
9161822427637
1053044444033
11205502299a9
12a344588281
1350047157b9
1427d2bc5877
1515a6cb748d
hexc59b1fb81

53044444033 has 4 divisors (see below), whose sum is σ = 60622221760. Its totient is φ = 45466666308.

The previous prime is 53044443997. The next prime is 53044444049. The reversal of 53044444033 is 33044444035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 53044444033 - 221 = 53042346881 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53044444033.

It is not an unprimeable number, because it can be changed into a prime (53044444333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3788888853 + ... + 3788888866.

It is an arithmetic number, because the mean of its divisors is an integer number (15155555440).

Almost surely, 253044444033 is an apocalyptic number.

It is an amenable number.

53044444033 is a deficient number, since it is larger than the sum of its proper divisors (7577777727).

53044444033 is an equidigital number, since it uses as much as digits as its factorization.

53044444033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7577777726.

The product of its (nonzero) digits is 138240, while the sum is 34.

Adding to 53044444033 its reverse (33044444035), we get a palindrome (86088888068).

The spelling of 53044444033 in words is "fifty-three billion, forty-four million, four hundred forty-four thousand, thirty-three".

Divisors: 1 7 7577777719 53044444033