Base | Representation |
---|---|
bin | 1111011100000010100… |
… | …11011110010110100011 |
3 | 1212201011222220102112021 |
4 | 13232001103132112203 |
5 | 32142330241441311 |
6 | 1043404023442311 |
7 | 53216024344456 |
oct | 7560123362643 |
9 | 1781158812467 |
10 | 530450343331 |
11 | 194a654320a7 |
12 | 8697a8b6397 |
13 | 3b0378ccbcc |
14 | 1b9613b949d |
15 | dbe9067171 |
hex | 7b814de5a3 |
530450343331 has 4 divisors (see below), whose sum is σ = 533963259664. Its totient is φ = 526937427000.
The previous prime is 530450343323. The next prime is 530450343343. The reversal of 530450343331 is 133343054035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530450343331 - 23 = 530450343323 is a prime.
It is a super-2 number, since 2×5304503433312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530450343931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1756457940 + ... + 1756458241.
It is an arithmetic number, because the mean of its divisors is an integer number (133490814916).
Almost surely, 2530450343331 is an apocalyptic number.
530450343331 is a deficient number, since it is larger than the sum of its proper divisors (3512916333).
530450343331 is a wasteful number, since it uses less digits than its factorization.
530450343331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3512916332.
The product of its (nonzero) digits is 97200, while the sum is 34.
Adding to 530450343331 its reverse (133343054035), we get a palindrome (663793397366).
The spelling of 530450343331 in words is "five hundred thirty billion, four hundred fifty million, three hundred forty-three thousand, three hundred thirty-one".
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