Base | Representation |
---|---|
bin | 100110100110000111011… |
… | …1011111110001111001001 |
3 | 200210002221011211211211012 |
4 | 1031030032323332033021 |
5 | 1143402142003304001 |
6 | 15140511515013305 |
7 | 1055145220235033 |
oct | 115141673761711 |
9 | 20702834754735 |
10 | 5304535213001 |
11 | 1765705925482 |
12 | 71807a13a235 |
13 | 2c62a567835b |
14 | 144a52d5cc53 |
15 | 92eb31272bb |
hex | 4d30eefe3c9 |
5304535213001 has 4 divisors (see below), whose sum is σ = 5310583714692. Its totient is φ = 5298486711312.
The previous prime is 5304535212997. The next prime is 5304535213039. The reversal of 5304535213001 is 1003125354035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1624184569225 + 3680350643776 = 1274435^2 + 1918424^2 .
It is a cyclic number.
It is not a de Polignac number, because 5304535213001 - 22 = 5304535212997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5304535213051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3024249530 + ... + 3024251283.
It is an arithmetic number, because the mean of its divisors is an integer number (1327645928673).
Almost surely, 25304535213001 is an apocalyptic number.
It is an amenable number.
5304535213001 is a deficient number, since it is larger than the sum of its proper divisors (6048501691).
5304535213001 is an equidigital number, since it uses as much as digits as its factorization.
5304535213001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6048501690.
The product of its (nonzero) digits is 27000, while the sum is 32.
The spelling of 5304535213001 in words is "five trillion, three hundred four billion, five hundred thirty-five million, two hundred thirteen thousand, one".
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