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530502830257 = 713477435531
BaseRepresentation
bin1111011100001000110…
…11101100100010110001
31212201022122200001001111
413232010123230202301
532142432211032012
61043413140433321
753220232440541
oct7560433544261
91781278601044
10530502830257
11194a92021324
12869943a8841
133b04574926a
141b96835d321
15dbed983ba7
hex7b846ec8b1

530502830257 has 4 divisors (see below), whose sum is σ = 530510337136. Its totient is φ = 530495323380.

The previous prime is 530502830251. The next prime is 530502830303. The reversal of 530502830257 is 752038205035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 530502830257 - 219 = 530502305969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530502830251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3646419 + ... + 3789112.

It is an arithmetic number, because the mean of its divisors is an integer number (132627584284).

Almost surely, 2530502830257 is an apocalyptic number.

It is an amenable number.

530502830257 is a deficient number, since it is larger than the sum of its proper divisors (7506879).

530502830257 is an equidigital number, since it uses as much as digits as its factorization.

530502830257 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7506878.

The product of its (nonzero) digits is 252000, while the sum is 40.

The spelling of 530502830257 in words is "five hundred thirty billion, five hundred two million, eight hundred thirty thousand, two hundred fifty-seven".

Divisors: 1 71347 7435531 530502830257