Base | Representation |
---|---|
bin | 1111011100001001000… |
… | …01101100001000100001 |
3 | 1212201022202121212022111 |
4 | 13232010201230020201 |
5 | 32142433111321231 |
6 | 1043413234235321 |
7 | 53220252003340 |
oct | 7560441541041 |
9 | 1781282555274 |
10 | 530504401441 |
11 | 194a929a4823 |
12 | 86994a25b41 |
13 | 3b045b79461 |
14 | 1b96864bb57 |
15 | dbedb944b1 |
hex | 7b8486c221 |
530504401441 has 4 divisors (see below), whose sum is σ = 606290744512. Its totient is φ = 454718058372.
The previous prime is 530504401439. The next prime is 530504401451. The reversal of 530504401441 is 144104405035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 530504401441 - 21 = 530504401439 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530504401451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37893171525 + ... + 37893171538.
It is an arithmetic number, because the mean of its divisors is an integer number (151572686128).
Almost surely, 2530504401441 is an apocalyptic number.
It is an amenable number.
530504401441 is a deficient number, since it is larger than the sum of its proper divisors (75786343071).
530504401441 is an equidigital number, since it uses as much as digits as its factorization.
530504401441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75786343070.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 530504401441 its reverse (144104405035), we get a palindrome (674608806476).
The spelling of 530504401441 in words is "five hundred thirty billion, five hundred four million, four hundred one thousand, four hundred forty-one".
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