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53051131 = 77578733
BaseRepresentation
bin1100101001011…
…1111011111011
310200211021110201
43022113323323
5102040114011
65133023031
71212633010
oct312277373
9120737421
1053051131
1127a45111
1215924a77
13acb6103
14708d707
1549cdcc1
hex3297efb

53051131 has 4 divisors (see below), whose sum is σ = 60629872. Its totient is φ = 45472392.

The previous prime is 53051051. The next prime is 53051147. The reversal of 53051131 is 13115035.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 53051131 - 29 = 53050619 is a prime.

It is a super-2 number, since 2×530511312 = 5628845000758322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53051099 and 53051108.

It is not an unprimeable number, because it can be changed into a prime (53051161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3789360 + ... + 3789373.

It is an arithmetic number, because the mean of its divisors is an integer number (15157468).

Almost surely, 253051131 is an apocalyptic number.

53051131 is a deficient number, since it is larger than the sum of its proper divisors (7578741).

53051131 is an equidigital number, since it uses as much as digits as its factorization.

53051131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7578740.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 53051131 is about 7283.6207342228. The cubic root of 53051131 is about 375.7493307157.

Adding to 53051131 its reverse (13115035), we get a palindrome (66166166).

The spelling of 53051131 in words is "fifty-three million, fifty-one thousand, one hundred thirty-one".

Divisors: 1 7 7578733 53051131