530535433 has 2 divisors, whose sum is σ = 530535434. Its totient is φ = 530535432.

The previous prime is 530535427. The next prime is 530535463. The reversal of 530535433 is 334535035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 525463929 + 5071504 = 22923^2 + 2252^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-530535433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530535395 and 530535404.

It is not a weakly prime, because it can be changed into another prime (530535463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265267716 + 265267717.

It is an arithmetic number, because the mean of its divisors is an integer number (265267717).

Almost surely, 2^530535433 is an apocalyptic number.

It is an amenable number.

530535433 is a deficient number, since it is larger than the sum of its proper divisors (1).

530535433 is an equidigital number, since it uses as much as digits as its factorization.

530535433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40500, while the sum is 31.

The square root of 530535433 is about 23033.3547925612. The cubic root of 530535433 is about 809.5396627319.

The spelling of 530535433 in words is "five hundred thirty million, five hundred thirty-five thousand, four hundred thirty-three".