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530552252025331 = 4711288345787773
BaseRepresentation
bin111100010100010001101001…
…0100001000100100111110011
32120120112022002122220000202121
41320220203102201010213303
51024020032003004302311
65120220201222255111
7216516064253326654
oct17050432241044763
92516468078800677
10530552252025331
11144060a45888328
124b6086b7887497
1319a06b2a439293
149502c1a49b52b
154150d35746b71
hex1e288d28449f3

530552252025331 has 4 divisors (see below), whose sum is σ = 541840597813152. Its totient is φ = 519263906237512.

The previous prime is 530552252025317. The next prime is 530552252025359. The reversal of 530552252025331 is 133520252255035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530552252025331 - 221 = 530552249928179 is a prime.

It is a super-2 number, since 2×5305522520253312 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530552252025931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5644172893840 + ... + 5644172893933.

It is an arithmetic number, because the mean of its divisors is an integer number (135460149453288).

Almost surely, 2530552252025331 is an apocalyptic number.

530552252025331 is a deficient number, since it is larger than the sum of its proper divisors (11288345787821).

530552252025331 is a wasteful number, since it uses less digits than its factorization.

530552252025331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11288345787820.

The product of its (nonzero) digits is 1350000, while the sum is 43.

The spelling of 530552252025331 in words is "five hundred thirty trillion, five hundred fifty-two billion, two hundred fifty-two million, twenty-five thousand, three hundred thirty-one".

Divisors: 1 47 11288345787773 530552252025331