Base | Representation |
---|---|
bin | 110001011010010101… |
… | …101101111101000011 |
3 | 12001221111210222001021 |
4 | 301122111231331003 |
5 | 1332124121001433 |
6 | 40212342050311 |
7 | 3555521120602 |
oct | 613225557503 |
9 | 161844728037 |
10 | 53055250243 |
11 | 2055633a856 |
12 | a348119997 |
13 | 5006a2a2c8 |
14 | 27d43d9a39 |
15 | 15a7bee22d |
hex | c5a56df43 |
53055250243 has 2 divisors, whose sum is σ = 53055250244. Its totient is φ = 53055250242.
The previous prime is 53055250159. The next prime is 53055250319. The reversal of 53055250243 is 34205255035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53055250243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53055250199 and 53055250208.
It is not a weakly prime, because it can be changed into another prime (53055250043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26527625121 + 26527625122.
It is an arithmetic number, because the mean of its divisors is an integer number (26527625122).
Almost surely, 253055250243 is an apocalyptic number.
53055250243 is a deficient number, since it is larger than the sum of its proper divisors (1).
53055250243 is an equidigital number, since it uses as much as digits as its factorization.
53055250243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 34.
The spelling of 53055250243 in words is "fifty-three billion, fifty-five million, two hundred fifty thousand, two hundred forty-three".
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