Base | Representation |
---|---|
bin | 100110100110100101001… |
… | …0011110000110001011001 |
3 | 200210012111121011120020021 |
4 | 1031031022103300301121 |
5 | 1143411212003230144 |
6 | 15141154420430441 |
7 | 1055212004001343 |
oct | 115151223606131 |
9 | 20705447146207 |
10 | 5305531305049 |
11 | 176607711a148 |
12 | 7182b7848421 |
13 | 2c6403b47831 |
14 | 144b09370293 |
15 | 930207d5884 |
hex | 4d34a4f0c59 |
5305531305049 has 2 divisors, whose sum is σ = 5305531305050. Its totient is φ = 5305531305048.
The previous prime is 5305531305031. The next prime is 5305531305143. The reversal of 5305531305049 is 9405031355035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5017062414400 + 288468890649 = 2239880^2 + 537093^2 .
It is a cyclic number.
It is not a de Polignac number, because 5305531305049 - 215 = 5305531272281 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5305531304996 and 5305531305014.
It is not a weakly prime, because it can be changed into another prime (5305531905049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652765652524 + 2652765652525.
It is an arithmetic number, because the mean of its divisors is an integer number (2652765652525).
Almost surely, 25305531305049 is an apocalyptic number.
It is an amenable number.
5305531305049 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305531305049 is an equidigital number, since it uses as much as digits as its factorization.
5305531305049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 607500, while the sum is 43.
The spelling of 5305531305049 in words is "five trillion, three hundred five billion, five hundred thirty-one million, three hundred five thousand, forty-nine".
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