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530641740113 = 2335791393271
BaseRepresentation
bin1111011100011001011…
…01100110000101010001
31212201200100001101112222
413232030231212011101
532143223241140423
61043435022030425
753223540240542
oct7561455460521
91781610041488
10530641740113
11195053479361
1286a12a18415
133b068464344
141b97c99c4c9
15dc0ac723c8
hex7b8cb66151

530641740113 has 8 divisors (see below), whose sum is σ = 533012553216. Its totient is φ = 528271725600.

The previous prime is 530641740053. The next prime is 530641740137. The reversal of 530641740113 is 311047146035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 530641740113 - 232 = 526346772817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530641740143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1152668 + ... + 1545938.

It is an arithmetic number, because the mean of its divisors is an integer number (66626569152).

Almost surely, 2530641740113 is an apocalyptic number.

It is an amenable number.

530641740113 is a deficient number, since it is larger than the sum of its proper divisors (2370813103).

530641740113 is a wasteful number, since it uses less digits than its factorization.

530641740113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 399295.

The product of its (nonzero) digits is 30240, while the sum is 35.

Adding to 530641740113 its reverse (311047146035), we get a palindrome (841688886148).

The spelling of 530641740113 in words is "five hundred thirty billion, six hundred forty-one million, seven hundred forty thousand, one hundred thirteen".

Divisors: 1 233 5791 393271 1349303 91632143 2277432361 530641740113