Base | Representation |
---|---|
bin | 111100010101000111110011… |
… | …1000001010011010110001011 |
3 | 2120120221102022101010012120222 |
4 | 1320222033213001103112023 |
5 | 1024023433202343314223 |
6 | 5120345434312540255 |
7 | 216530352423054233 |
oct | 17052174701232613 |
9 | 2516842271105528 |
10 | 530668560135563 |
11 | 1440a62aa771a83 |
12 | 4b6271570b168b |
13 | 19a14aa47ac395 |
14 | 95086d1374cc3 |
15 | 4153d915390c8 |
hex | 1e2a3e705358b |
530668560135563 has 4 divisors (see below), whose sum is σ = 531814712533728. Its totient is φ = 529522407737400.
The previous prime is 530668560135557. The next prime is 530668560135587. The reversal of 530668560135563 is 365531065866035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530668560135563 - 212 = 530668560131467 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 530668560135496 and 530668560135505.
It is not an unprimeable number, because it can be changed into a prime (530668560135533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 573076198388 + ... + 573076199313.
It is an arithmetic number, because the mean of its divisors is an integer number (132953678133432).
Almost surely, 2530668560135563 is an apocalyptic number.
530668560135563 is a deficient number, since it is larger than the sum of its proper divisors (1146152398165).
530668560135563 is a wasteful number, since it uses less digits than its factorization.
530668560135563 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1146152398164.
The product of its (nonzero) digits is 174960000, while the sum is 62.
The spelling of 530668560135563 in words is "five hundred thirty trillion, six hundred sixty-eight billion, five hundred sixty million, one hundred thirty-five thousand, five hundred sixty-three".
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