Base | Representation |
---|---|
bin | 110001011011000101… |
… | …010110010101100011 |
3 | 12001222101022022212020 |
4 | 301123011112111203 |
5 | 1332140320031134 |
6 | 40213505432523 |
7 | 3556032213465 |
oct | 613305262543 |
9 | 161871268766 |
10 | 53067736419 |
11 | 20562398905 |
12 | a35033b743 |
13 | 50094ac689 |
14 | 27d5d2a135 |
15 | 15a8d68b49 |
hex | c5b156563 |
53067736419 has 4 divisors (see below), whose sum is σ = 70756981896. Its totient is φ = 35378490944.
The previous prime is 53067736411. The next prime is 53067736429. The reversal of 53067736419 is 91463776035.
53067736419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53067736419 - 23 = 53067736411 is a prime.
It is a super-2 number, since 2×530677364192 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53067736411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8844622734 + ... + 8844622739.
It is an arithmetic number, because the mean of its divisors is an integer number (17689245474).
Almost surely, 253067736419 is an apocalyptic number.
53067736419 is a deficient number, since it is larger than the sum of its proper divisors (17689245477).
53067736419 is a wasteful number, since it uses less digits than its factorization.
53067736419 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17689245476.
The product of its (nonzero) digits is 2857680, while the sum is 51.
The spelling of 53067736419 in words is "fifty-three billion, sixty-seven million, seven hundred thirty-six thousand, four hundred nineteen".
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