Base | Representation |
---|---|
bin | 110001011011101111… |
… | …011111100000000001 |
3 | 12002000011002121021221 |
4 | 301123233133200001 |
5 | 1332201132042001 |
6 | 40214542315041 |
7 | 3556225135255 |
oct | 613357374001 |
9 | 162004077257 |
10 | 53078784001 |
11 | 20568654041 |
12 | a353b88a81 |
13 | 500b879cc9 |
14 | 27d75a4265 |
15 | 15a9cec1a1 |
hex | c5bbdf801 |
53078784001 has 2 divisors, whose sum is σ = 53078784002. Its totient is φ = 53078784000.
The previous prime is 53078783981. The next prime is 53078784029. The reversal of 53078784001 is 10048787035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50534590401 + 2544193600 = 224799^2 + 50440^2 .
It is a cyclic number.
It is not a de Polignac number, because 53078784001 - 25 = 53078783969 is a prime.
It is a super-2 number, since 2×530787840012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53078784301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26539392000 + 26539392001.
It is an arithmetic number, because the mean of its divisors is an integer number (26539392001).
Almost surely, 253078784001 is an apocalyptic number.
It is an amenable number.
53078784001 is a deficient number, since it is larger than the sum of its proper divisors (1).
53078784001 is an equidigital number, since it uses as much as digits as its factorization.
53078784001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 188160, while the sum is 43.
The spelling of 53078784001 in words is "fifty-three billion, seventy-eight million, seven hundred eighty-four thousand, one".
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