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53080750053307 = 160639330435013
BaseRepresentation
bin11000001000110110100110…
…10000000101011110111011
320221221110200201220021022001
430010123103100011132323
523424133334003201212
6304520543202441431
714115646320000154
oct1404332320053673
9227843621807261
1053080750053307
1115a05468658009
125b534a3963277
1323806548a07c2
14d1719cb2292b
15620b43630657
hex3046d34057bb

53080750053307 has 4 divisors (see below), whose sum is σ = 53081080648960. Its totient is φ = 53080419457656.

The previous prime is 53080750053301. The next prime is 53080750053319. The reversal of 53080750053307 is 70335005708035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53080750053307 - 215 = 53080750020539 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53080750053301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165056868 + ... + 165378145.

It is an arithmetic number, because the mean of its divisors is an integer number (13270270162240).

Almost surely, 253080750053307 is an apocalyptic number.

53080750053307 is a deficient number, since it is larger than the sum of its proper divisors (330595653).

53080750053307 is a wasteful number, since it uses less digits than its factorization.

53080750053307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 330595652.

The product of its (nonzero) digits is 1323000, while the sum is 46.

The spelling of 53080750053307 in words is "fifty-three trillion, eighty billion, seven hundred fifty million, fifty-three thousand, three hundred seven".

Divisors: 1 160639 330435013 53080750053307