Base | Representation |
---|---|
bin | 1111011100111010111… |
… | …01100001011011101001 |
3 | 1212202101220210122011012 |
4 | 13232131131201123221 |
5 | 32144312210130213 |
6 | 1043522540513305 |
7 | 53233521552542 |
oct | 7563535413351 |
9 | 1782356718135 |
10 | 530922739433 |
11 | 1951880552a9 |
12 | 86a90b4b835 |
13 | 3b0b173b828 |
14 | 1b9a80274c9 |
15 | dc2577b4a8 |
hex | 7b9d7616e9 |
530922739433 has 2 divisors, whose sum is σ = 530922739434. Its totient is φ = 530922739432.
The previous prime is 530922739327. The next prime is 530922739481. The reversal of 530922739433 is 334937229035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 370944338704 + 159978400729 = 609052^2 + 399973^2 .
It is a cyclic number.
It is not a de Polignac number, because 530922739433 - 218 = 530922477289 is a prime.
It is a super-2 number, since 2×5309227394332 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (530922739483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265461369716 + 265461369717.
It is an arithmetic number, because the mean of its divisors is an integer number (265461369717).
Almost surely, 2530922739433 is an apocalyptic number.
It is an amenable number.
530922739433 is a deficient number, since it is larger than the sum of its proper divisors (1).
530922739433 is an equidigital number, since it uses as much as digits as its factorization.
530922739433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3674160, while the sum is 50.
The spelling of 530922739433 in words is "five hundred thirty billion, nine hundred twenty-two million, seven hundred thirty-nine thousand, four hundred thirty-three".
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